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0=4x^2+4x-528
We move all terms to the left:
0-(4x^2+4x-528)=0
We add all the numbers together, and all the variables
-(4x^2+4x-528)=0
We get rid of parentheses
-4x^2-4x+528=0
a = -4; b = -4; c = +528;
Δ = b2-4ac
Δ = -42-4·(-4)·528
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-92}{2*-4}=\frac{-88}{-8} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+92}{2*-4}=\frac{96}{-8} =-12 $
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